IndieMate Posted April 19, 2015 Share Posted April 19, 2015 Can someone explain how to solve this? x2 + y2 = 34 x + y + xy = 23 ty. c: Link to comment Share on other sites More sharing options...
Professional Map Painter Posted April 19, 2015 Share Posted April 19, 2015 Here's some help with your meth. Link to comment Share on other sites More sharing options...
The Penguins Posted April 19, 2015 Share Posted April 19, 2015 Do a systems of equations, I believe Link to comment Share on other sites More sharing options...
IndieMate Posted April 19, 2015 Author Share Posted April 19, 2015 Do a systems of equations, I believe I don't know how to solve the system. Link to comment Share on other sites More sharing options...
IndieMate Posted April 19, 2015 Author Share Posted April 19, 2015 Here's some help with your meth. ty. Much appreciated Link to comment Share on other sites More sharing options...
harsheldon Posted April 19, 2015 Share Posted April 19, 2015 Just looking to find x and y ? simultaneous equations? Link to comment Share on other sites More sharing options...
IndieMate Posted April 19, 2015 Author Share Posted April 19, 2015 Just looking to find x and y ? simultaneous equations? Yes. Link to comment Share on other sites More sharing options...
Vince Posted April 19, 2015 Share Posted April 19, 2015 solve the top function for y then plug the result in for y into the second one after that you will have what x should be then plug x into the first one and solve again for y Link to comment Share on other sites More sharing options...
λngelღмander Posted April 19, 2015 Share Posted April 19, 2015 I looked at it for a few seconds, figured out that it has to be five and three. 25+9 = 34, 5+3+15 = 23. However, I don't know which one is 5 and which one is three. Link to comment Share on other sites More sharing options...
IndieMate Posted April 19, 2015 Author Share Posted April 19, 2015 I looked at it for a few seconds, figured out that it has to be five and three. 25+9 = 34, 5+3+15 = 23. However, I don't know which one is 5 and which one is three. I know the answer, but I need the solution. Link to comment Share on other sites More sharing options...
Mike Hawk Posted April 19, 2015 Share Posted April 19, 2015 Can someone explain how to solve this? x2 + y2 = 34 x + y + xy = 23 ty. c: x^2 + y^2 = 34 y^2 = 34 - x^2 y = sqrt(34-x^2) x + sqrt(34-x^2) + x(sqrt(34-x^2) = 23 (square everything) x^2 + 34-x^2 + x^2 * 34-x^2 = 23*23 x^4 + 34x^2 + 34 = 529 x^4 + 34x^2 = 495 Dunno how. Hardest system of equations i've seen. Link to comment Share on other sites More sharing options...
Rosalina Posted April 19, 2015 Share Posted April 19, 2015 x = 3, y = 5 and then the reverse would hold true as well since they are identical y = 3, x= 5 Link to comment Share on other sites More sharing options...
Mike Hawk Posted April 19, 2015 Share Posted April 19, 2015 x = 3, y = 5 and then the reverse would hold true as well since they are identical y = 3, x= 5 I know the answer, but I need the solution. Link to comment Share on other sites More sharing options...
IndieMate Posted April 19, 2015 Author Share Posted April 19, 2015 x^2 + y^2 = 34 y^2 = 34 - x^2 y = sqrt(34-x^2) x + sqrt(34-x^2) + x(sqrt(34-x^2) = 23 (square everything) x^2 + 34-x^2 + x^2 * 34-x^2 = 23*23 x^4 + 34x^2 + 34 = 529 x^4 + 34x^2 = 495 Dunno how. Hardest system of equations i've seen. I did the same shiz, then I get a biquadratic equation, but the discriminant is negative. Maybe there's a mistake in one of the equations :c Link to comment Share on other sites More sharing options...
Carnage Posted April 19, 2015 Share Posted April 19, 2015 What type of math are you in? Can you use derivatives or have a graphing calculator to use? Link to comment Share on other sites More sharing options...
Roller Posted April 19, 2015 Share Posted April 19, 2015 Alright, this is how you do it. x2 + y2 = 34 . . . (1) x + y + xy = 23 . . . (2) Factorizing both equations: (x+y)2-2xy=34 . . . (3) (x+y)2-xy=23 . . . (4) -xy=11 xy=-11 Substituting xy=-11 into (2): x+y-11=23 x+y=34 . . . (5) x=34-y x=-y+34 Substituting x=-10-y into (1) (-y+34)2+y2=34 y2-68y+1156+y2=34 2y2+20y=-1122 2y2+20y+1122=0 y2+10y+561=0 And shit, I'm stuck here. However, I'm sure this is how it should be done. I'll probably try again later. Link to comment Share on other sites More sharing options...
.Dusk Posted April 19, 2015 Share Posted April 19, 2015 sample text Link to comment Share on other sites More sharing options...
Carnage Posted April 19, 2015 Share Posted April 19, 2015 x + y + xy = 23 . . . (2) (x+y)2-xy=23 . . . (4) How are these the same? Link to comment Share on other sites More sharing options...
Carnage Posted April 19, 2015 Share Posted April 19, 2015 This shows a step by step solution without needing to graph or use derivatives, I would think you can ignore the imaginary solutions unless you are asked for those too. I hope you know your quadratic formula. https://www.symbolab.com/solver/system-of-equations-calculator/x%5E%7B2%7D%20%2B%20y%5E%7B2%7D%20%3D%2034%2C%20x%2By%2Bxy%3D23/?origin=button Let know if you need any explanations. Link to comment Share on other sites More sharing options...
Roller Posted April 19, 2015 Share Posted April 19, 2015 How are these the same? Oh no :c Link to comment Share on other sites More sharing options...
IndieMate Posted April 19, 2015 Author Share Posted April 19, 2015 This shows a step by step solution without needing to graph or use derivatives, I would think you can ignore the imaginary solutions unless you are asked for those too. I hope you know your quadratic formula. https://www.symbolab.com/solver/system-of-equations-calculator/x%5E%7B2%7D%20%2B%20y%5E%7B2%7D%20%3D%2034%2C%20x%2By%2Bxy%3D23/?origin=button Let know if you need any explanations. Thank you this helped/explained a lot. <3 Link to comment Share on other sites More sharing options...
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