AwesomeMcCoolName Posted September 15, 2013 Share Posted September 15, 2013 In the first part of this lab you will accurately measure about 15 g of table sugar (sucrose, C12H22O11), make a stock solution, then make three dilutions. Assume you measure 15.01 g of sucrose.15grams of sugar=.04385 mols You will then dissolve the sucrose into enough water to make 50.00 mL of solution. This is called the stock solution. Determine the concentration of sucrose in the stock solution. You will then take 30.00 mL of the stock solution and dilute it to 50.00 mL with water. This is called dilution #1. Determine the concentration of sucrose in dilution #1. You will then take 30.00 mL of dilution #1 and dilute it to 50.00 mL with water. This is called dilution #2. Determine the concentration of sucrose in dilution #2. You will then take 30.00 mL of dilution #2 and dilute it to 50.00 mL with water. This is called dilution #3. Determine the concentration of sucrose in dilution #3. How do i figure out how much water needs to be added for the total to equal 50? Link to comment Share on other sites More sharing options...
Woifi The Viking Posted September 15, 2013 Share Posted September 15, 2013 How do i figure out how much water needs to be added for the total to equal 50? Hmm I think 15g of sugar completely dissolve in 50ml of water so you need...50ml of water? Without more information (about the solubility), that has to be the case. 1. 0.877 mol/l c = n/v c = 0.04385 mol / 0.05 liter => c = 0.877 mol/l 2. 0.5262 mol/l 0.877 mol/l ...... 50 ml x mol/l ..... 30 ml ------------------------ 0.877 mol/l * 30 ml / 50 ml = 0.5263 mol/l 3. 0.31572 mol/l same as #2 4. 0.189432 mol/l same as #2 K? Link to comment Share on other sites More sharing options...
Silent Scream Posted September 15, 2013 Share Posted September 15, 2013 I don't fuckin' know, I finished Chemistry with a C+. Link to comment Share on other sites More sharing options...
Triforce of Charmanders Posted September 15, 2013 Share Posted September 15, 2013 i thought this would be about chemistry sets. I feel stupid now. Link to comment Share on other sites More sharing options...
Pyrous Posted September 15, 2013 Share Posted September 15, 2013 i thought this would be about chemistry sets. I feel stupid now. You're not the only one. Link to comment Share on other sites More sharing options...
AwesomeMcCoolName Posted September 15, 2013 Author Share Posted September 15, 2013 i thought this would be about chemistry sets. I feel stupid now. You're not the only one. #General Discussion section, not Economy/Trade Section Link to comment Share on other sites More sharing options...
MC22 Posted September 15, 2013 Share Posted September 15, 2013 #General Discussion section, not Economy/Trade Section science section wouldve made more sense Link to comment Share on other sites More sharing options...
AwesomeMcCoolName Posted September 15, 2013 Author Share Posted September 15, 2013 science section wouldve made more sense Except its not a thought provoking question/thread, so no. Link to comment Share on other sites More sharing options...
Avenging Flame Posted September 16, 2013 Share Posted September 16, 2013 *Comes in expecting chemistry sets* *Sees actualy chemistry* *walks out* Link to comment Share on other sites More sharing options...
grimdercell Posted September 16, 2013 Share Posted September 16, 2013 In the first part of this lab you will accurately measure about 15 g of table sugar (sucrose, C12H22O11), make a stock solution, then make three dilutions. Assume you measure 15.01 g of sucrose. 15grams of sugar=.04385 mols You will then dissolve the sucrose into enough water to make 50.00 mL of solution. This is called the stock solution. Determine the concentration of sucrose in the stock solution. You will then take 30.00 mL of the stock solution and dilute it to 50.00 mL with water. This is called dilution #1. Determine the concentration of sucrose in dilution #1. You will then take 30.00 mL of dilution #1 and dilute it to 50.00 mL with water. This is called dilution #2. Determine the concentration of sucrose in dilution #2. You will then take 30.00 mL of dilution #2 and dilute it to 50.00 mL with water. This is called dilution #3. Determine the concentration of sucrose in dilution #3. How do i figure out how much water needs to be added for the total to equal 50? What level of chem is this? Link to comment Share on other sites More sharing options...
AwesomeMcCoolName Posted September 16, 2013 Author Share Posted September 16, 2013 What level of chem is this? begining of chem1, easy shit Link to comment Share on other sites More sharing options...
Woifi The Viking Posted September 16, 2013 Share Posted September 16, 2013 begining of chem1, easy shit Extrem easy shit. One of the most basic formulars and tripple multiplication.^^ Link to comment Share on other sites More sharing options...
HeavyLord Posted September 16, 2013 Share Posted September 16, 2013 I frickin thought this was for chemistry set Link to comment Share on other sites More sharing options...
sushi-sacha Posted September 16, 2013 Share Posted September 16, 2013 I believe the answer you are looking for is fourty two. Yes, 42. C: Link to comment Share on other sites More sharing options...
AwesomeMcCoolName Posted September 17, 2013 Author Share Posted September 17, 2013 More Chem shit: http://imgur.com/GNVWhcv,H8pmBcU,OpSkLEW,T5XxYrg,TK7ewl6,dIDyXtq If anyone can figure out any of it, that would be greatly appreciated. /Couldn't do chem in Hs, and i still can't :/ Link to comment Share on other sites More sharing options...
Recommended Posts
Archived
This topic is now archived and is closed to further replies.